CODEWITHSUNDEEP
pythonstringreplace
user3514137
user3514137

Reputation: 89

python pattern detect and replace string

I have a question on Python string operation:

Here's a string in which there are multiple .(dot),

like: "a3a.b1b2b.cccc.ded.f.g"

The question is to find the content before the last .(dot), which is "a3a.b1b2b.cccc.ded.f" in this example (We call it as STRING_BEFORE_LAST_DOT)

and we need to replace STRING_BEFORE_LAST_DOT to be STRING_BEFORE_LAST_DOT + "_Approved". So the result should be: "a3a.b1b2b.cccc.ded.f_Approved.g".

And some more examples:

"a.b" -> "a_Approved.b"
"first.second.c" -> "first.second_Approved.c"

I can def a function to do so, I'm wondering if there's any advance way, like use .replace() to make it happen. Thanks.

Upvotes: 1

Views: 228

Answers (6)

The fourth bird
The fourth bird

Reputation: 163362

You can use a pattern to match from the last dot until the end of the string .[^.]*$

Then replace with _Approved and add the full match after it using \g<0>

print(re.sub(r"\.[^.]*$", r"_Approved\g<0>", "a3a.b1b2b.cccc.ded.f.g"))

Output

a3a.b1b2b.cccc.ded.f_Approved.g

Upvotes: 0

Meric Gunduz
Meric Gunduz

Reputation: 1

Here is an alternative. You can access every dot's index with this:

import re
str = "a3a.b1b2b.cccc.ded.f"
# Finds every dot's starting index. (For ending of matched value d.end())
dots = [d.start(0) for d in re.finditer(r'\.+', str)]
# _Approved added
str = str[:dots[-1]] + "_Approved" + str[dots[-1]:]

Upvotes: 0

Jan Christoph Terasa
Jan Christoph Terasa

Reputation: 5935

An example of how to do it with a regexp:

import re
s = "a3a.b1b2b.cccc.ded.f.g" 
no_ext = re.split(r'\.[^\.]*$', s)[0]

Upvotes: 0

Martin Mwangi
Martin Mwangi

Reputation: 21

# your String
string = 'a3a.b1b2b.cccc.ded.f.g'
# find the last dot character in your string
StringIndex = string.rfind('.')
# create a temporary list of your string and swap the last dot with your preferred string (_Approved.)
temp = list(string)
temp[StringIndex] = '_Approved.'
# replace
string = ''.join(temp)
# print
print('Old String: a3a.b1b2b.cccc.ded.f.g \nNew String: '+ string)

# OUTPUT
# Old String: a3a.b1b2b.cccc.ded.f.g 
# New String: a3a.b1b2b.cccc.ded.f_Approved.g

Upvotes: 1

sushanth
sushanth

Reputation: 8302

Here is a solution you can try out,

def _replace(input_):
    sub_ = input_[input_.rfind("."):]
    return input_.replace(sub_, f"_Approved{sub_}")


print(_replace("a.b"))
print(_replace("first.second.c"))

a_Approved.b
first.second_Approved.c

Upvotes: 0

Cyrille
Cyrille

Reputation: 14523

You could use join + rsplit with a limit of 1:

>>> "_Approved.".join("a.b".rsplit(".",1))
'a_Approved.b'
>>> "_Approved.".join("first.second.c".rsplit(".",1))
'first.second_Approved.c'

Upvotes: 2

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