CODEWITHSUNDEEP
pythonpython-3.x
Abdullah Md
Abdullah Md

Reputation: 151

Print specific value of XML response

My code return XML response, i want to print only link that contain https

like this:

https://xxxx.xxxx.com/playback/presentation/5

Ex of response:

<playback>
<format>
<type>presentation</type>
<url>https://xxxx.xxxx.com/playback/presentation/5</url>
<processingTime>915</processingTime>
<length>0</length>
<size>114961</size>
<preview>

I tried this:

x = re.search("<url>.{45}", full_responsee).group()
xx = x.replace('<url>', '')
soup = xx
print(x)

But i need solution more simple.

Any kind of help please?

Upvotes: 0

Views: 204

Answers (2)

Scott Hunter
Scott Hunter

Reputation: 49893

Assuming the url element only appears once & without any attributes, this will do the trick:

full_responsee.split("<url>")[1].split("</url>")[0]

Upvotes: 1

&#193;lvaro Zamora
&#193;lvaro Zamora

Reputation: 176

You can use ElementTree and do this

from xml.etree import ElementTree as et

tree = et.parse(your-xml)
url = tree.find('playback/format/url')
print(url)

and if you want to change the value:

tree.find('url').text = "newValue"

Upvotes: 1

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