CODEWITHSUNDEEP
pythonlist-comprehension
AdaoBMF
AdaoBMF

Reputation: 55

How do i pass the last else in list comprehension

I'm trying make a if, elif list comprehension line... found this code in other question:

>>> l = [1, 2, 3, 4, 5]
>>> ['yes' if v == 1 else 'no' if v == 2 else 'idle' for v in l]
['yes', 'no', 'idle', 'idle', 'idle']

My question is: Can I pass the last 'else' as a third action? I've tried use pass but got a syntax error.

I have this:

# list = [(code, qty),(code, qty)]
>>>storehouse = [('BSA2199',2000),('PPF5239',251),('BSA1212',989)]
>>>buyList = [(cod, 1000) if qty < 200 else (cod, 500) for cod, qty 
in storehouse]

I want to ignore the items that are > 1000.

Thanks, hope I had made my self clear(first question in here).

Upvotes: 1

Views: 82

Answers (2)

Samwise
Samwise

Reputation: 71454

I might encode this relationship in a dictionary so you can use it for both the filtering and the mapping:

>>> l = [1, 2, 3, 4, 5]
>>> d = {1: 'yes', 2: 'no'}
>>> [d[v] for v in l if v in d]
['yes', 'no']

Upvotes: 1

Prune
Prune

Reputation: 77837

You need to first filter for the desired values, at the outer for expression. Within that, you choose your yes/no response:

['yes' if v == 1 else 'no' 
       for v in l    if v in [1, 2]]

Output:

['yes', 'no']

Upvotes: 1

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