CODEWITHSUNDEEP
javascriptarrays
PeopleCallMeLucifer
PeopleCallMeLucifer

Reputation: 45

Stuck sorting and seperating a nested array in JS

so I'm trying to find any way to separate this array based on ID's.

[ [ 1, 123412341234, 2.44 ], [ 1, 123912341234, 23.44 ], [ 1, 623412341234, 82.44 ], [ 2, 123412341234, 22.44 ], [ 2, 123412381234, 2.44 ], [ 2, 723412341234, 29.44 ], [ 3, 123412341234, 24.44 ], [ 3, 123412377234, 34.44 ], [ 3, 520312341234, 54.44 ], [ 4, 123412341234, 12.44 ], [ 4, 938412341234, 19.44 ], [ 4, 603412341234, 10.44 ] ]

weather in separate array or in the same array but with an additional [] around the data with same ID

so this
[
    [[ 1, 123412341234, 2.44 ], [ 1, 123912341234, 23.44 ], [ 1, 623412341234, 82.44 ]], 
    [[ 2, 123412341234, 22.44 ], [ 2, 123412381234, 2.44 ], [ 2, 723412341234, 29.44 ]], 
    [[ 3, 123412341234, 24.44 ], [ 3, 123412377234, 34.44 ], [ 3, 520312341234, 54.44 ]], 
    [[ 4, 123412341234, 12.44 ], [ 4, 938412341234, 19.44 ], [ 4, 603412341234, 10.44 ]]
]

or this

[[ 1, 123412341234, 2.44 ], [ 1, 123912341234, 23.44 ]] 
[[ 2, 123412341234, 22.44 ], [ 2, 123412381234, 2.44 ], [ 2, 723412341234, 29.44 ]]  
[[ 3, 123412341234, 24.44 ], [ 3, 123412377234, 34.44 ], [ 3, 520312341234, 54.44 ]]     
[[ 4, 123412341234, 12.44 ], [ 4, 938412341234, 19.44 ], [ 4, 603412341234, 10.44 ]]

This is what I tried to make by myself but it's not working ( the c[i] is not working)

 for(let i = 0; i < this.z.length;i++) {
     for (let j = 0; j < this.z.length; j++) {
         if(this.z[j][0]==i){
             this.c[i].push(this.z[j]) 
         }                      
     }        
 }

Upvotes: 1

Views: 113

Answers (2)

me.nkr
me.nkr

Reputation: 108

const array = [
  [1, 123412341234, 2.44],
  [1, 123912341234, 23.44],
  [1, 623412341234, 82.44],
  [2, 123412341234, 22.44],
  [2, 123412381234, 2.44],
  [2, 723412341234, 29.44],
  [3, 123412341234, 24.44],
  [3, 123412377234, 34.44],
  [3, 520312341234, 54.44],
  [4, 123412341234, 12.44],
  [4, 938412341234, 19.44],
  [4, 603412341234, 10.44]
];
let result = [];
for (let id = 0; id < 4; id++) {
  result[id] = [];
  for (let index = 0; index < array.length; index++) {
    if (array[index][0] === id+1) {
      result[id].push(array[index]);
    }
  }
}


console.log(result) ;

Upvotes: 1

Nina Scholz
Nina Scholz

Reputation: 386654

You could group the array by checking the predecessor and build a new group for a changing first value of the inner array. This approach needs a sorted array.

const
    data = [[1, 123412341234, 2.44], [1, 123912341234, 23.44], [1, 623412341234, 82.44], [2, 123412341234, 22.44], [2, 123412381234, 2.44], [2, 723412341234, 29.44], [3, 123412341234, 24.44], [3, 123412377234, 34.44], [3, 520312341234, 54.44], [4, 123412341234, 12.44], [4, 938412341234, 19.44], [4, 603412341234, 10.44]],
    result = data.reduce((r, row, i, a) => {
        if (!i || a[i - 1][0] !== row[0]) r.push([]);
        r[r.length - 1].push(row);
        return r;
    }, []);

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 1

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