CODEWITHSUNDEEP
c++
laksh
laksh

Reputation: 2329

Question over the usage of rint

for(i = 0; i < 181; i++)
    {
       unsigned int index = rint(i/db);
        assert(index >= 0 && index < data.ranges_count);
      this->laser_ranges[i*2][0] = data.ranges[index] * 1e3;
    }

what is the meaning of rint(i/db)? I am not sure how rint is used...

Upvotes: 1

Views: 1697

Answers (3)

Benjamin Bannier
Benjamin Bannier

Reputation: 58744

rint rounds to the nearest integer with some error checking.

What really happens here depends on the type of i and db of course.

Upvotes: 0

Armen Tsirunyan
Armen Tsirunyan

Reputation: 133082

rint is a function that rounds a floating point number to an integer. It is a non-standard function. If db is of an integral type, then i/db will truncate to an integer and the code will not work as you have expected. Otherwise the rint(i/db) is i/db rounded to the nearest integer.

As to why the rounding is needed here(insteas of truncation) depends heavily on the context of your problem which we have absolutely no idea about.

Upvotes: 5

Cat Plus Plus
Cat Plus Plus

Reputation: 129914

It's a call to function named rint with a single argument, which in this case is i divided by db.

Upvotes: 2

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