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Daaviid
Daaviid

Reputation: 97

Convert day and month to number of the year (1 - 365) in R

Let's suppose I have a data frame with two columns, one for months and the second one for days. Here is a simple example

month=c(2, 4, ,7, 8, 11, 11, 12)
day=c(21,4,6,8,15,20,30)
monthday=data.frame(month,day)

I want to determine a number (from 1 to 365) that corresponds to the year's day. How can I do that?

Upvotes: 1

Views: 1626

Answers (2)

henhesu
henhesu

Reputation: 851

You can use the yday function from the lubridate package:

library(dplyr)
library(tidyr)
library(lubridate)

month=c(2, 4,7, 8, 11, 11, 12)
day=c(21,4,6,8,15,20,30)
# also define a year so you can parse an actual date
year = 2021
monthday=tibble(month,day, year)

monthday %>% 
  # combine into one variable
  tidyr::unite("date", year, month, day, sep = "-", remove = FALSE) %>% 
  # parse as date
  dplyr::mutate(date = lubridate::ymd(date)) %>% 
  # extract day of year
  dplyr::mutate(doy = lubridate::yday(date))

#> # A tibble: 7 x 5
#>   date       month   day  year   doy
#>   <date>     <dbl> <dbl> <dbl> <dbl>
#> 1 2021-02-21     2    21  2021    52
#> 2 2021-04-04     4     4  2021    94
#> 3 2021-07-06     7     6  2021   187
#> 4 2021-08-08     8     8  2021   220
#> 5 2021-11-15    11    15  2021   319
#> 6 2021-11-20    11    20  2021   324
#> 7 2021-12-30    12    30  2021   364

Created on 2021-05-31 by the reprex package (v2.0.0)

Upvotes: 5

Vinicius B. de S. Moreira
Vinicius B. de S. Moreira

Reputation: 531

First you need to provide the year and transform all in "POSIXt". Then i recommend:

as.numeric(strftime(date, format = "%j"))

Upvotes: 3

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