CODEWITHSUNDEEP
pythonlistenerkeyboard-events
Nils Schmidt
Nils Schmidt

Reputation: 27

button pressed stays true

My code should press "p" twice, after pressing the letter "u" on the keyboard, . This also works. But when I press "u" twice in quick succession, the code hangs up and the function somehow keeps calling itself, even though I don't press "u" at all. Does anyone know what could be the reason for this?

from pynput.keyboard import Listener
import keyboard  # using module keyboard
import time



def on_press(key):  # The function that's called when a key is pressed
   
    if keyboard.is_pressed('u'): #'u' is pressed 
            
            keyboard.press('p')
            keyboard.release('p')
            time.sleep(0.01)
            keyboard.press('p')
            keyboard.release('p')
            time.sleep(1)
          
    else:
            pass



with Listener(on_press=on_press) as listener:  # Create an instance of Listener
    listener.join()  # Join the listener thread to the main thread to keep waiting for keys

Upvotes: 0

Views: 255

Answers (1)

user16096234
user16096234

Reputation:

It's probably because the code under the keyboard.is_pressed('u') takes 1.001 seconds to execute (or slightly more) because of the time.sleep calls. If you press U twice in less than 1.001 seconds, it is breaking because the function can't finish before you call it again.

Upvotes: 1

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