CODEWITHSUNDEEP
javascriptregexsplit
Fabio
Fabio

Reputation: 336

Split a string at every occurrence of a date format yyyy-mm-dd

I'm trying to split a string at every occurrence of a specific pattern. I have a string like this one:

91.240.109.42FrancePrestashop PI block
2021-06-02213.186.52.66FrancePrestaShop
2012-06-29

And I want to split the string at every occurrence of the date format yyyy-mm-dd mantaining the date in the splitted array, so the result I want to obtain is this one:

[91.240.109.42FrancePrestashop PI block 2021-06-02,213.186.52.66FrancePrestaShop 2012-06-29]

I have tried to split based on the date format but it does not work:

var splitted_string= result.split(/^\d{4}-\d{2}-\d{2}$/)

Upvotes: 0

Views: 941

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626845

You can use

const text = `91.240.109.42FrancePrestashop PI block
2021-06-02213.186.52.66FrancePrestaShop
2012-06-29`;
console.log( text.split(/(?<=\d{4}-\d{2}-\d{2})/).map(x=>x.replaceAll("\n"," ")) )

The (?<=\d{4}-\d{2}-\d{2}) pattern is a positive lookbehind that matches a location that is immediately preceded with four digits, -, two digits, - and two digits.

See this regex demo.

With .map(x=>x.replaceAll("\n"," "), you replace each LF Char with a space.

Upvotes: 1

Tim Biegeleisen
Tim Biegeleisen

Reputation: 521249

Use match here, with the following regex pattern:

[\s\S]+?(?:\d{4}-\d{2}-\d{2}|$)

This will match all content up until the first date, repeteadly through the text.

var input = `91.240.109.42FrancePrestashop PI block
2021-06-02213.186.52.66FrancePrestaShop
2012-06-29`
var matches = input.match(/[\s\S]+?(?:\d{4}-\d{2}-\d{2}|$)/g);
console.log(matches);

Note that I use logic such that should the input not end in a date, the final split value would still be included.

Upvotes: 1

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