CODEWITHSUNDEEP
pythonanagram
Vahid
Vahid

Reputation: 65

looking for a key in a dictionary using Counter() for anagram

I am trying to look for keys with similar letters (anagram) in an imaginary dictionay and I have this incomplete code:

from collections import Counter
diction = {'crazy':'dd', 'abd':'ddd','cat':'bad'}
word = input('what is the word?')
new=[]
for i in dic:
    if(Counter(word) == Counter(....):
        new.append(...)
    else:
        continue
 
print(f'{word} and {new} are anagrams')

I have no idea how to check for the keys and if they match the given input. Appreciate your help

Upvotes: 1

Views: 63

Answers (1)

Kraigolas
Kraigolas

Reputation: 5590

I actually think Counter is a good solution here, probably better than sorting because it is O(n). For example, Counter("arc") == Counter("car") returns True. So you were on the right track.

There are typos in your code (dic should be diction). Your for loop was already iterating through keys, so you were close:

from collections import Counter
diction = {'crazy':'dd', 'abd':'ddd','cat':'bad'}
word = input('what is the word?')
new=[]
for i in diction:
    if(Counter(word) == Counter(i)):
        new.append(i)
    else:
        continue
 
print(f'{word} and {new} are anagrams')

If I input "tac", it will print:

tac and ['cat'] are anagrams

Upvotes: 2

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