Reputation: 541
Consider the loop below. This is a simplified example of a problem I am trying to solve. I want to limit the number of times doSomething function is called in each second. Since the loop works very fast, I thought I could use a rate limiter. Let's assume that I have found an appropriate value by running it with different x numbers.
unsigned int incrementionRate = x;
unsigned int counter == 0;
while (true) {
double seconds = getElapsedSeconds();
print(seconds);
counter = (counter + 1) % incrementionRate;
if (counter == 0) {
doSomething();
}
}
I wonder if the number of calls to doSomething function would be less if I was working on a lower clock rate. In that case, I would like to limit the number of calls to doSomething function to once for each second. The second loop I have written is below.
float epsilon = 0.0001;
while (true) {
double seconds = getElapsedSeconds();
print(seconds);
if (abs(seconds - floor(seconds)) <= epsilon) {
doSomething();
}
}
Would that do the trick for different clock cycles or are there still problems? Also, I would like to know if there is a better way of doing this. I have never worked with clock rates before and trying to understand how concerns differ when working with limited resources.
Note: Using sleep is not an option.
Upvotes: 0
Views: 127
Reputation: 541
I decided to go with a much more simple approach at the end. Used an adjustable time interval and just stored the latest update time, without introducing any new mechanism. Honestly, now I don't know why I couldn't think of it at first. Overthinking is a problem. :)
double lastUpdateTimestamp = 0;
const double updateInterval = 1.0;
while (true) {
double seconds = getElapsedSeconds();
print(seconds);
if ((elapsedSeconds - lastUpdateTimestamp) >= updateInterval) {
doSomething();
lastUpdateTimestamp = elapsedSeconds;
}
}
Upvotes: 0
Reputation: 25536
Ted's answer is fine if you are really doing something else in the loop; if not, though, this results in a busy wait which is just consuming up your CPU for nothing.
In such a case you should rather prefer letting your thread sleep:
std::chrono::milliseconds offset(200);
auto next = std::chrono::steady_clock::now();
for(;;)
{
doSomething();
next += offset;
std::this_thread::sleep_until(next);
}
You'll need to include chrono
and thread
headers for.
Upvotes: 2
Reputation: 117443
If I understand the issue proberly, you could use a std::chrono::steady_clock
that you just add a second to every time a second has passed.
Example:
#include <chrono>
auto end_time = std::chrono::steady_clock::now();
while (true) {
// only call doSomething once a second
if(end_time < std::chrono::steady_clock::now()) {
doSomething();
// set a new end time a second after the previous one
end_time += std::chrono::seconds(1);
}
// do something else
}
Upvotes: 4