CODEWITHSUNDEEP
laravellaravel-livewire
Awminux
Awminux

Reputation: 103

Get checkbox status in livewire

I have a form that has 2 checkboxes in this form. When I submit the information I want to test what the value of the first checkbox is. I use ‍‍‍‍‍‍`dd () but it shows me the value of Null. What is the problem? How can I solve this?

this is view:

<div class="form-group">
    <div class="custom-control custom-switch">
        <input class="custom-control-input" id="deposit" type="checkbox"> <label class="custom-control-label" for="deposit">Deposit</label>
    </div>
</div>
<div class="col-md-6">
    <div class="form-group">
        <div class="custom-control custom-switch">
            <input class="custom-control-input" id="withdraw" type="checkbox"> <label class="custom-control-label" for="withdraw">withdraw</label>
        </div>
    </div>
</div>
<button class="btn btn-round btn-outline-primary"><span class="w-100px">create</span></button>

and this is component:

<?php

namespace App\Http\Livewire\Backend\Currency;


use Livewire\Component;

class Networks extends Component
{
    
    public $deposit;
    public $withdraw;



    public function addNetwork()
    {
        dd($this->deposit1);
    }


    public function render()
    {
        return view('livewire.backend.currency.networks');
    }
}

Upvotes: 0

Views: 3364

Answers (1)

Peppermintology
Peppermintology

Reputation: 10210

You bind to the checkboxes like you would any other public property, using wire:model.

<div class="form-group">
    <div class="custom-control custom-switch">
        <!-- bind to $deposit -->
        <input wire:model="deposit"
                class="custom-control-input"
                id="deposit"
                type="checkbox">
        <label class="custom-control-label" for="deposit">Deposit</label>
    </div>
</div>
<div class="col-md-6">
    <div class="form-group">
        <div class="custom-control custom-switch">
            <!--bind to $withdraw -->
            <input wire:model="withdraw"
                    class="custom-control-input"
                    id="withdraw"
                    type="checkbox">
            <label class="custom-control-label" for="withdraw">withdraw</label>
        </div>
    </div>
</div>

Now when the form is submitted, if deposit or withdraw is checked, their value will be true.

Something you might want to do is give $deposit and $withdraw a default value of false as otherwise their initial values will be null.

public $deposit = false;

public $withdraw = false;

Upvotes: 1

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