CODEWITHSUNDEEP
linuxunixgrep
JDKTeam
JDKTeam

Reputation: 25

GREP to show files WITH text and WITHOUT text

I am trying to search for files with specific text but excluding a certain text and showing only the files.

Here is my code:

grep -v "TEXT1" *.* | grep -ils "ABC2"

However, it returns: (standard input)

Please suggest. Thanks a lot.

The output should only show the filenames.

Upvotes: 1

Views: 1311

Answers (2)

Sundeep
Sundeep

Reputation: 23667

Here's one way to do it, assuming you want to match these terms anywhere in the file.

grep -LZ 'TEXT1' *.* | xargs -0 grep -li 'ABC2'
  • -L will match files not containing the given search term
    • use -LiZ if you want to match TEXT1 irrespective of case
  • The -Z option is needed to separate filenames with NUL character and xargs -0 will then separate out filenames based on NUL character

If you want to check these two conditions on same line instead of anywhere in the file:

grep -lP '^(?!.*TEXT1).*(?i:ABC2)' *.*
  • -P enables PCRE, which I assume you have since linux is tagged
  • (?!regexp) is a negative lookahead construct, so ^(?!.*TEXT1) will ensure the line doesn't have TEXT1
  • (?i:ABC2) will match ABC2 case insensitively
  • Use grep -liP '^(?!.*TEXT1).*ABC2' if you want to match both terms irrespective of case

Upvotes: 2

anubhava
anubhava

Reputation: 785146

(standard input)

This error is due to use of grep -l in a pipeline as your second grep command is reading input from stdin not from a file and -l option is printing (standard input) instead of the filename.

You can use this alternate solution in a single awk command:

awk '/ABC2/ && !/TEXT1/ {print FILENAME; nextfile}' *.* 2>/dev/null

Upvotes: 1

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