CODEWITHSUNDEEP
flutterdartnumber-formatting
KiritoCode
KiritoCode

Reputation: 24

Flutter - Number Format

Is there a way to format a number :

from 1 to 1.00,
from 2.5 to 2.50,
from 2.1234 to 2.1234
so basically the number will have a minimum of 2 decimal places

Thanks for your help.

Upvotes: 0

Views: 5604

Answers (3)

Corvus Albus
Corvus Albus

Reputation: 185

A non elegant way using Intl package:

var f = NumberFormat('#.00###############', 'en_Us');
print(f.format(2.123400))

and you will get

2.1234

but if your number have more decimal digit than you have '#' in format string then it's not show. For example

var f = NumberFormat('#.00##', 'en_Us');
print(f.format(2.123456))

you will get

2.1234

I think that way works most of cases. Or you can make format function by yourself. Like this:

String formatNumber(double number) {
  int precision = 0;
  while ((number * pow(10, precision)) % 10 != 0) {
    precision++;
  }
  return number.toStringAsFixed(max(precision - 1, 2));
}

In this case you don't use Intl package. There is no problem with number of digit after dot. BUT i belive that is a much slower than using intl package.

Upvotes: 2

Burak Cabadan
Burak Cabadan

Reputation: 182

you can use someDoubleValue.toStringAsFixed(2) what this does is it basically adds or removes floating points from value

Note: if you parse double from this result string again, it will convert back (5.00 => 5)

Example:

String parseNumber(value) {
  String strValue = value.toString();

  List parsedNumber = strValue.split(".");
 
  String newValue;
  if (parsedNumber.length == 1) {
    newValue = value.toStringAsFixed(2);
  } else {
    String decimalPlace = parsedNumber[1];
  
    if (decimalPlace.length > 2) {
    newValue = value.toString();
    } else {
    newValue = value.toStringAsFixed(2);
    }
  }
  
  return newValue;

}

Upvotes: 0

Rohan Thacker
Rohan Thacker

Reputation: 6357

The Intl package has a set of formatting classes than can help with this use case in particular the NumberFormat Class

Upvotes: 0

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