CODEWITHSUNDEEP
selenium-webdriver
ali
ali

Reputation: 27

Selenium Loop Through Links

In selenium, in python, I have to loop through Jira1, jira2, jira3 links

for i in range(1,4):
driver.find_element(By.XPATH,"//a[text()='Jira']+/str(i)").click()

It is giving me an error NoSuchElementException: no such element: Unable to locate element: {"method":"xpath","selector":"//a[text()='Jira+str(i)']"} (Session info: chrome=91.0.4472.77)

How do I resolve that

Upvotes: 0

Views: 164

Answers (1)

Siebe Jongebloed
Siebe Jongebloed

Reputation: 4869

To use a variable in building the XPath you should correctly insert that variable like @Martheen is commenting.

So in stead of:

driver.find_element(By.XPATH,"//a[text()='Jira']+/str(i)").click()

Use this:

driver.find_element(By.XPATH,"//a[text()='Jira" + i +"']").click()

this will build i.e. the XPath: //a[text()='Jira1']

To have better controle over your loop and to know what is going on your loop, you could first build the XPath string and then use it, i.e. like this:

for i in range(1,4):
   XPathInLoop = "//a[text()='Jira" + i + "']"
   print(XPathInLoop)
   driver.find_element(By.XPATH,XPathInLoop).click()

Upvotes: 0

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