CODEWITHSUNDEEP
shell
Pratiksha Dalal
Pratiksha Dalal

Reputation: 11

I am trying to pass the parameter from a file to the shell script, but because of space it is breaking

Script :

#script.sh
clear
echo ----------------------------------------------
echo ***********"starting shell script"************
echo ----------------------------------------------
ls

curl --location --request POST "http://localhost:8081/adddetails"  --header "Content-Type: application/json" --data "{ \"batch_id\": \"$1\", \"modality\": {     \"modality\" : \"$2\" }, \"start_time\": \"$3\"} ] } "

echo \"$1\"
echo \"$2\"
echo \"$3\"
echo ----------------------------------------------
echo ***********"ending shell script"************
echo ----------------------------------------------

My input file from where I a taking parameter: 1 a 2015-12-31 18:30:00

here $3 should be 2015-12-31 18:30:00 but because of space it is breaking. I tried many escape characters but nothing is working

I ran below command:

bash scripts.sh $(cat inputs.txt)

Upvotes: 0

Views: 44

Answers (2)

William Pursell
William Pursell

Reputation: 212624

The script itself looks fine, the trouble is with the way you are calling it. bash has no way of reading your mind to determine that you want the 3rd and 4th columns of your input to be merged into a single argument. Perhaps you could try separating the arguments by tab instead of spaces in inputs.txt and specify tab in IFS. Something like:

$ cat -tve inputs.txt 
1^Ia^I2015-12-31 18:30:00$
$ (IFS=$'\t'; ./script.sh $(cat inputs.txt) )

Another option (which doesn't require the subshell or modification of the input file) which seems a bit cleaner is:

$ read a b date < inputs.txt 
$ ./script.sh "$a" "$b" "$date"

With this particular example, you don't need to set IFS because read will concat all of the remaining arguments into the final variable, but you may want to use a similar technique as above and do:

$ IFS=$'\t' read a b date c < inputs.txt 
$ ./script.sh "$a" "$b" "$date"

For example, this would be necessary if there were more inputs on the line after the date, and this would rely on modifying the input file to use tab as the field separator.

Upvotes: 1

Alejandro A.
Alejandro A.

Reputation: 136

Shell's default behavior is to split args by space, so not much to do there, your $3 argument will be the date only.

What you could do is create a variable inside your script concatenating the variables you want to handle as a single value.

DATETIME="$3 $4"
echo $DATETIME

Another option would be to pass your arguments with quotes to the command:

./script.sh arg1 arg2 "YYYY-MM-DD hh:mm:ss"

But this approach doesn't work if you are passing the arguments from a file.

Upvotes: 1

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