CODEWITHSUNDEEP
bash
user12879631
user12879631

Reputation:

Bash script excluding first element

I have a bash script that is gathering active users on a machine and then I am going to curl away the data. The issue is that the first item in the list won't show up, it is gathering everything after the first. Can anyone explain why?

#!/bin/bash
users=$(ps -eo ruser,rgroup | grep users | sort | uniq | cut -d ' ' -f1)
while read -r users
do
   newVar=$newVar$(awk '{print "user_name{name=\""$users"\"}", 1.0}');
done <<< "$users"

Then I curl newVar which should be a concatenation of all users in the format that is required.

Upvotes: 0

Views: 160

Answers (1)

Barmar
Barmar

Reputation: 780818

There's no need for the users variable or the while read loop. Just pipe the output of the ps pipe directly to awk.

You don't need cut, since awk can select the first column with $1. And sort | uniq can be combined into sort -u.

newVar=$(ps -eo ruser,rgroup | grep users | sort -u | awk '{printf ("username{name=\"%s\"} 1.0", $1)

Upvotes: 0

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