Reputation: 151
I have an application where I am receiving a string with some repetitive characters. I am receiving input as a String. How to remove the characters from specific index?
main.rs
fn main() {
let s:String = "{\"name\":\"xx/yyyy/machine/zzz/test_int4\",\"status\":\"online\",\"timestamp\":\"2021-06-11 18:20:42.231770800 UTC\",\"value\":7}8668982856274}".to_string();
println!("{}", s);
}
how can I get result
"{\"name\":\"xx/yyyy/machine/zzz/test_int4\",\"status\":\"online\",\"timestamp\":\"2021-06-11 18:20:42.231770800 UTC\",\"value\":7}"
instead of
"{\"name\":\"xx/yyyy/machine/zzz/test_int4\",\"status\":\"online\",\"timestamp\":\"2021-06-11 18:20:42.231770800 UTC\",\"value\":7}}8668982856274}"
Upvotes: 0
Views: 1513
Reputation: 3445
String indexing works only with bytes, thus you need to find an index for the appropriate byte slice like this:
let mut s = "{\"name\":\"xx/yyyy/machine/zzz/test_int4\",\"status\":\"online\",\"timestamp\":\"2021-06-11 18:20:42.231770800 UTC\",\"value\":7}8668982856274}";
let closing_bracket_idx = s
.as_bytes()
.iter()
.position(|&x| x == b'}')
.map(|i| i + 1)
.unwrap_or_else(|| s.len());
let v: serde_json::Value = serde_json::from_str(&s[..closing_bracket_idx]).unwrap();
println!("{:?}", v);
However, keep in mind, this approach doesn't really work in general for more complex cases, for example }
in a json string value, or nested objects, or a type other than an object at the upmost level (e.g. [1, {2: 3}, 4]
). More neat way is using parser capabilities to ignore of the trailing, as an example for serde_json:
let v = serde_json::Deserializer::from_str(s)
.into_iter::<serde_json::Value>()
.next()
.expect("empty input")
.expect("invalid json value");
println!("{:?}", v);
Upvotes: 1