CODEWITHSUNDEEP
laravel-8
Abdullah Al Shahed
Abdullah Al Shahed

Reputation: 89

Too few arguments to function App\Http\Controllers\ProjectController::index(), 0 passed in C:\xampp\htdocs\ContentBaseApp\

I have error:

ArgumentCountError Too few arguments to function App\Http\Controllers\ProjectController::index(), 0 passed in C:\xampp\htdocs\ContentBaseApp\vendor\laravel\framework\src\Illuminate\Routing\Controller.php on line 54 and exactly 1 expected

enter image description here

In my ProjectController.php How can i solve this This is my ProjectController.php

public function index($product_id)
{
    // $projects = Project::whereIn('product_id',Product::where('user_id',Auth::id())->pluck('id')->toArray())->latest()->paginate(20);

    $product = Product::where('user_id', Auth::id())->where('id', $product_id)->firstOrFail();
    $projects = Project::where('product_id', $product->id)->latest()->paginate(20);

    return view('projects.index', compact('projects'))
            ->with('i', (request()->input('page', 1) - 1) * 5);
}

I wrote index method code because I want; suppose I have two id 1 & 2 if I click id 1 it will take me to index.blade.php where I can upload new data like data_1 and data_2 those data will show on index.blade.php

And if I click id 2 it will take me to index.blade.php where I don't want to see data of id 1 as I uploaded data1 and data2.

If I upload new data for id 2 I can see those data in index.blde.php

Upvotes: 0

Views: 14486

Answers (1)

Peppermintology
Peppermintology

Reputation: 10210

The index function on your ProjectController expects one argument ($product_id) as per the error message you're seeing.

Whenever you access of reference the index route, it needs to be provided with the $product_id parameter otherwise an error will be thrown (the one you're seeing).

If you're following convention, what you likely want to do is define two routes:

  1. An index route that displays all resources and takes zero arguments
  2. A show route that displays information for a single resource and requires one argument which identifies a resource.

For example:

web.php

Route::get('/projects', [ProjectController::class, 'index')
    ->name('projects.index');

Route::get('/projects/{product}', [ProjectController::class, 'show'])
    ->name('projects.show');

ProjectController.php

public function index()
{
    return view('projects.index', [
        'projects' => Project::paginate(20),
    ]);
}

public function show(Product $product)
{
    return view('projects.show', [
        'projects' => $product->projects()->latest()->paginate(20),
    ]);
}

If you visit /projects you will return all project resources, but if you visit /projects/2 you will get only the projects related to Product with id of 2.

You can use the route() helper to generate your URLs.

<a href="{{ route('projects.show', 2) }}"> ... </a>

That would create a link that would take you to the projects for product 2.

Upvotes: 2

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