Reputation: 798
Im developing google sheet side bar. For that link to google side bar css package is used.
bt1
has an inline style background-color
declarations with important!
.
however when page loads the color is something gray. I went over the google css trying to understand, with not much success.
bt2.onClick()
- change bt1.disable
. You can see the inline statement have effect only when bt1is disabled.
If not linking to google css - behavior as expected.
My understanding is that inline style must always win. especially when specifying important!
my questions are:
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://ssl.gstatic.com/docs/script/css/add-ons1.css">
</head>
<body>
<button id="bt1" style="background-color: rgb(43, 226, 137) !important;">bt1</button>
<button id="bt2" onclick="bt2OnClick()">bt2</button>
<script>
function bt2OnClick(){
let bt = document.getElementById("bt1");
// Switch state
bt.disabled = !bt.disabled;
}
</script>
</body>
</html>
Upvotes: 0
Views: 93
Reputation: 2321
Your style is in fact being applied but the add-ons1.css
your adding add a background
property with a linear-gradient
so your background-color
does not change the background-image
property that represent the gradient
So if you want to override it, just select the background
property instead of background-color
And you dont need you !important
anymore :)
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://ssl.gstatic.com/docs/script/css/add-ons1.css">
</head>
<body>
<button id="bt1" style="background: rgb(43, 226, 137)">bt1</button>
<button id="bt2" onclick="bt2OnClick()">bt2</button>
<script>
function bt2OnClick(){
let bt = document.getElementById("bt1");
// Switch state
bt.disabled = !bt.disabled;
}
</script>
</body>
</html>
Upvotes: 1