CODEWITHSUNDEEP
c++visual-studio-2008char
zia
zia

Reputation: 117

How to initialize char**?

Here is my piece of code:

char** filename;
*(filename) = "initialize";
printf("filename = %s",*(filename));

I got this error when I tried to run it: 

Run-Time Check Failure #3 - The variable 'filename' is being used without being initialized.

Is there any way to fix this?

Upvotes: 1

Views: 8266

Answers (7)

Sami Haroon
Sami Haroon

Reputation: 909

For initializing char **variable you can also use the following way.

    //define length
    int length = 1;
    std::string init_str = "your_string";
    //inititlize char **var length
    char **my_var = static_cast<char **>(calloc(length, sizeof(char *)));
    my_var[0] = static_cast<char *>(calloc(init_str.size() + 1, sizeof(char)));
    //copy string value in char **my_var
    strcpy(argv[0], api_flag.c_str());

This way you can initialize for multiple values and assign values for length (N)

Upvotes: 0

Mateen Ulhaq
Mateen Ulhaq

Reputation: 27201

@Naszta's answer is the one you should listen to. But to correct all these other wrong answers on new:

size_t len = strlen("initialize") + 1;
char* sz = new char [len];
strncpy(sz, "initialize", strlen("initialize"));

The real C++ way of doing it is better, of course.

string filename = "initialize";
cout << "filename = " << filename;

Upvotes: 0

Joel
Joel

Reputation: 670

You haven't allocated the char* that you're trying to assign to:

char** filename = new char*;
*filename = "initialize";

Upvotes: -1

Naszta
Naszta

Reputation: 7734

C way:

#include <string.h>
#include <stdio.h>
#include <stdlib.h>

char * filename = (char*) malloc( 100 ); // reserve 100 bytes in memory
strcpy(filename,"initialize");           // copy "initialize" into the memory
printf("filename = %s",filename);        // print out
free(filename);                          // free memory
filename = 0;                            // invalid pointers value is NULL

C++ way:

#include <string>
#include <iostream>

string filename("initialize");           // create string object
cout << "filename = " << filename;       // write out to stanard out

Upvotes: 4

Nick
Nick

Reputation: 1748

char *a  =  "abcdefg";
char **fileName = &a;

Upvotes: 5

Ajay
Ajay

Reputation: 18411

char** filename = new char*;   
*(filename) = "initialize";    
printf("filename = %s",*(filename));

But why do you need that stuff?

Upvotes: 0

Patrick87
Patrick87

Reputation: 28292

You need to allocate room for filename using new or malloc. As it is, filename is just a pointer to a random area of memory you have not requested...

  filename = new char*;

Upvotes: 1

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