Reputation: 9
I have a project made using CodeIgniter 3 where I have created 2 view pages. On the 1st page, the user sees a table with the columns (Order Number, Customer, Status of the order, Date Created, and comments), but I show only the pending orders. On the second page, I have the exact columns but I show only the completed orders.
Here's what the 1st page looks like:
Now what I want to do is on the 1st page when I check the check boxes in each row I want and after pressing the Change Status button to be able to change the status in the database. I have managed to pass the id's of the rows checked by doing this:
function change_status(x){
var vals = [];
jQuery('.checkorders:checked').each(function(){
vals.push(jQuery(this).val());
});
$.ajax({
type: "POST",
url: '<?php echo base_url();?>change_status.php' ,
data:{'myData':vals,'type':x},
success: function(response)
{
alert('ok');
}
});
}
Now the code in the change_status.php is
<?php
include('application/views/backend/admin/dbc.php');
mysqli_query($conn,"SET character_set_results = 'utf8', character_set_client = 'utf8', character_set_connection = 'utf8', character_set_database = 'utf8', character_set_server = 'utf8'");
$type=$_POST['type'];
$mydat= $_POST['myData'];
foreach($mydat as $dt)
{
$sql0 = "SELECT * FROM orders WHERE id=".$dt." order by id ASC";
$result0 = $conn->query($sql0);
if ($result0->num_rows > 0) {
while($row0 = $result0->fetch_assoc()) {
$orders_id[]=array("id"=>$row0['id']);
echo $row0['id']."<br/>";
}
}
}
if($type==1)
$out = "**";
{
foreach($orders_id as $ID)
{
$out.= $elispisID['id']." - ";
//$this->db->where('id', $elispisID['id']);
//$this->db->update('elipsis', array('status' => 0));
}
echo $out;
$output1="csv";
$output2="csv/patoures/";
$output3=$output2.date("Y")."/";
$output4=$output3.date("m");
if (!is_dir($output1)) {mkdir($output1,0777);}
if (!is_dir($output2)) {mkdir($output2,0777);}
if (!is_dir($output3)) {mkdir($output3,0777);}
if (!is_dir($output4)) {mkdir($output4,0777);}
$output_forder=$output4."/".date("dHi");
file_put_contents($output_forder,$out);
}
$conn->close();
?>
The $out variable is to help me see if i pass the id's correctly, as every time i check the checkboxes and press the Change Status button it creates a file with the id's selected. But if I uncomment the 2 lines that I try to update the database it doesn't update it or prints anything
Does anyone have any idea what I am doing wrong?
Upvotes: 0
Views: 56
Reputation: 23664
Ok, heres your page in codeigniter
Keep everything as it is in your JS, but change the url to this
url: '<?php echo base_url();?>changestatus/change',
Then create this file, called Changestatus.php in your controllers
folder. I saw that you were selecting and looping through your DB just to get the list of id's that you're sending through the ajax (did I get that wrong)? All you need to do is update your elipses
table and set status=0
where id in (array of ids)
.
<?php
// controllers/Changestatus.php
class Changestatus extends CI_Controller {
public function __construct() {
parent::__construct();
$this->load->library('db'); // this should already be autoloaded in config/config.php but just in case
}
function change() {
$type = $this->input->post('type');
$mydat = $this->input->post('myData');
$this->db->set('status', '0');
$this->db->where_in('id', $mydat);
$done = $this->db->update('elipsis');
if (!$done) {
die("error: <pre>".print_r($this->db->error(),1)."</pre>");
}
// I have no idea what all this is....
$output1 = "csv";
$output2 = "csv/patoures/";
$output3 = $output2 . date("Y") . "/";
$output4 = $output3 . date("m");
if (!is_dir($output1)) {mkdir($output1, 0777);}
if (!is_dir($output2)) {mkdir($output2, 0777);}
if (!is_dir($output3)) {mkdir($output3, 0777);}
if (!is_dir($output4)) {mkdir($output4, 0777);}
$output_forder = $output4 . "/" . date("dHi");
file_put_contents($output_forder, $out);
}
}
?>
Upvotes: 1