CODEWITHSUNDEEP
javascriptstring
Example
Example

Reputation: 3

How to display firstly vowels and then consonants in string?

Basically I want to display vowels and consonants from string but I quite don't understand why my code below doesn't work properly.

const word = "javascriptloops";
let array = word.split("");
for (let i = 0; i < array.length; i++) {
  if (
    array[i] === "a" ||
    array[i] === "e" ||
    array[i] === "i" ||
    array[i] === "o" ||
    array[i] === "u"
  ) {
    console.log(array[i]);
    array.splice(i, 1);
  }
}
for (let item of array) {
  console.log(item);
}

The result it shows is: The result

Can someone explain what's the reason why it doesn't include this second "o" with the vowels?

Upvotes: 0

Views: 189

Answers (2)

DecPK
DecPK

Reputation: 25408

AKX explained it beautifully. So this is just an alternative if you want vowels and consonants individually.

const word = "javascriptloops";
let vowel = word.match(/[aeiou]/g);
let consonants = word.match(/[^aeiou]/g);

console.log(vowel);
console.log(consonants);

If you want result in one loop then you could do something like

const word = "javascriptloops",
  vowel = [],
  consonants = [];

for (let char of word) {
  if (char.match(/[aeiou]/)) vowel.push(char);
  else consonants.push(char);
}

console.log(vowel);
console.log(consonants);

Upvotes: 0

AKX
AKX

Reputation: 169051

Since you're modifying the same array you're iterating over, you'll need to "skip back" one cell after removing an item.

That is, add i--; after array.splice(i, 1);

To visualize this, you can try

console.log(array.join(""), array.length);
console.log(" ".repeat(i) + "^", i);

in your loop.

Without this skipping back, the output is

javascriptloops 15
 ^ 1
jvascriptloops 14
  ^ 2
jvscriptloops 13
     ^ 5
jvscrptloops 12
        ^ 8

With the fix, it's

javascriptloops 15
 ^ 1
jvascriptloops 14
  ^ 2
jvscriptloops 13
     ^ 5
jvscrptloops 12
        ^ 8
jvscrptlops 11
        ^ 8

This is made even more obvious with a string with more subsequent vowels, say, daemonium:

No fix:

daemonium 9
 ^ 1
demonium 8
   ^ 3
demnium 7
    ^ 4

With fix:

daemonium 9
 ^ 1
demonium 8
 ^ 1
dmonium 7
  ^ 2
dmnium 6
   ^ 3
dmnum 5
   ^ 3

Upvotes: 1

Related Questions