CODEWITHSUNDEEP
pythonpython-typingmypytypeddict
ignoring_gravity
ignoring_gravity

Reputation: 10476

Iterating over TypedDict's keys

Here's an example:

from typing import TypedDict

class Foo(TypedDict):
    a: str
    b: int

foo = Foo(a='2', b=4)

for key in foo:
    print(foo[key])

I get

main.py:10: note: Revealed type is 'Any'
main.py:10: error: TypedDict key must be a string literal; expected one of ('a', 'b')
Found 1 error in 1 file (checked 1 source file)

I find this surprising - isn't it known that key is one of foo's keys, and hence that foo[key] should be valid?

Playground URL: https://mypy-play.net/?mypy=latest&python=3.9&gist=8972284897f25314f9c790eab4cb8548

Upvotes: 7

Views: 3155

Answers (1)

Zichzheng
Zichzheng

Reputation: 1280

I think it's known issue which was discussed here. If you want it to work now, just try # type: ignore which should overwritten the warning.

from typing import TypedDict

class Foo(TypedDict):
    a: str
    b: int

foo = Foo(a='2', b=4)

for key in foo:
    print(foo[key]) # type: ignore

playground URL:https://mypy-play.net/?mypy=latest&python=3.9&gist=85e30e0187088219797a283c31d7ec7c

Upvotes: 6

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