Reputation: 81
The required covariance matrix is
where t is 1D time and k={0, 1}
A sample from the kernel should look like:
with the orange sequence corresponding to k=0, and the blue one to k=1.
Upvotes: 0
Views: 463
Reputation: 1537
It sounds like you're looking for a kernel for different discrete outputs. You can achieve this in GPflow for example with the Coregion
kernel, for which there is a tutorial notebook.
To construct a coregionalization kernel that is block-diagonal (all off-diagonal entries are zero), you can set rank=0
. Note that you need to explicitly specify which kernel should act on which dimensions:
import gpflow
k_time = gpflow.kernels.SquaredExponential(active_dims=[0])
k_coreg = gpflow.kernels.Coregion(output_dim=2, rank=0, active_dims=[1])
You can combine them with *
as in the notebook, or with +
as specified in the question:
k = k_time + k_coreg
You can see that the k_coreg
term is block-diagonal as you specified: Evaluating
test_inputs = np.array([
[0.1, 0.0],
[0.5, 0.0],
[0.7, 1.0],
[0.1, 1.0],
])
k_coreg(test_inputs)
returns
<tf.Tensor: shape=(4, 4), dtype=float64, numpy=
array([[1., 1., 0., 0.],
[1., 1., 0., 0.],
[0., 0., 1., 1.],
[0., 0., 1., 1.]])>
And you can get samples as in the graph in the question by running
import numpy as np
num_inputs = 51
num_outputs = 2
X = np.linspace(0, 5, num_inputs)
Q = np.arange(num_outputs)
XX, QQ = np.meshgrid(X, Q, indexing='ij')
pts = np.c_[XX.flatten(), QQ.flatten()]
K = k(pts)
L = np.linalg.cholesky(K + 1e-8 * np.eye(len(K)))
num_samples = 3
v = np.random.randn(len(L), num_samples)
f = L @ v
import matplotlib.pyplot as plt
for i in range(num_samples):
plt.plot(X, f[:, i].reshape(num_inputs, num_outputs))
Upvotes: 1
Reputation: 276
In GPflow, you can construct this kernel using a sum kernel consisting of a Squared Exponential (RBF) and a White kernel.
import gpflow
kernel = gpflow.kernels.SquaredExponential() + gpflow.kernels.White()
Upvotes: 0