Reputation: 59365
I have attempted to create a function that will replace multiple regular expression values from an array. This works if the array does not contain quotation marks of any kind, this is problematic when I want to use a comma in my pattern. So I've been trying to find an alternative way of serving the pattern with no luck. Any ideas?
function removeCharacters(str){
//ucpa = unwanted character pattern array
//var ucpa = [/{/g,/}/g,/--/g,/---/g,/-/g,/^.\s/];
var ucpa = ["/{/","/}/","/--/","/---/","/-/","/^.\s/","/^,\s/"];
for (var i = 0; i < ucpa.length; i++){
//does not work
var pattern = new RegExp(ucpa[i],"g");
var str = str.replace(pattern, " ");
}
return str;
}
WORKING:
function removeCharacters(str){
//ucpa = unwanted character pattern array
var ucpa = [/{/g,/}/g,/--/g,/---/g,/-/g,/^.\s/,/^,\s/];
for (var i = 0; i < ucpa.length; i++){
var str = str.replace(ucpa[i], " ");
}
return str;
}
REFINED:
function removeCharacters(str){
var pattern = /[{}]|-{1,3}|^[.,]\s/g;
str = str.replace(pattern, " ");
return str;
}
Upvotes: 0
Views: 2484
Reputation: 336158
You can also wrap all that into a single regex:
var str = str.replace(/[{}]|-{1,3}|^[.,]\s/g, " ")
although I'm not sure if that's exactly what you want since some of your regexes are nonsensical, for example ,^\s
could never match.
Upvotes: 3
Reputation: 887451
The RegExp
constructor takes raw expressions, not wrapped in /
characters.
Therefore, all of your regexes contain two /
s each, which isn't what you want.
Instead, you should make an array of actual regex literals:
var ucpa = [ /.../g, /",\/.../g, ... ];
Upvotes: 5