Joi Lynn Marie Jover
Joi Lynn Marie Jover

Reputation: 21

Invalid Indirection in C++

This is my program. I dont know what to do next because I dont know what is invalid indirection. The error is found from line 46 to 52.

#include<iostream.h>
#include<conio.h>
#include<math.h>
#include<stdio.h>


int main()
{
int d, c;

double fx, fx1, fx2, fx3, fd, fd1, fd2, fd3, x, xi, e, y, er;

double in[9] = {0, 0, 0, 0, 0, 0, 0, 0, 0};

clrscr();


cout << "\n\nEnter degree: ";

cin >> d;

if(d == 9)
{
    cout << "\n\nThis is only limited up to the dehree of 8.";
}

else if(d == 0)
{
    cout << "\n\nCannot solve equation. There is no variable present.";
}

else
{

    for(c = d; c >= 0; c--)
    {
        cout << "\nCoeff for x^" << c << " term: ";
        cin >> in[c];
    }

    cout << "\n\nEnter xi = ";
    cin >> x;

    do
    {
        **fx1 = (c[8] * pow(x,8)) + (c[7] * pow(x,7)) + (c[6] * pow(x,6));
        fx2 = (c[5] * pow(x,5)) + (c[4] * pow(x,4)) + (c[3] * pow(x,3));
        fx3 = (c[2] * pow(x,2)) + (c[1] * x) + c[0];
        fx = (fx1 + fx2 + fx3);

        fd1 = (d * c[0] * pow(x, d-1)) + ((d-1) * c[1] * pow(x, d-2)) + ((d-2) * c[2] * pow(x, d-3));
        fd2 = ((d-3) * c[3] * pow(x, d-4)) + ((d-4) * c[4] * pow(x, d-5)) + ((d-5) * c[5] * pow(x, d-6));
        fd3 = ((d-6) * c[6] * pow(x, d-7)) + (c[7]);**

        fd = (fd1 + fd2 + fd3);

        y = x;

        x = (x - (fx/fd));

        e = x - y;

        if(e >=0)
        {
            er = e;
        }

        else
        {
            er = -(e);
        }
    }while(er > 0.0000000001);

    cout << "\n\nThe root of the equation is " << x << ".";



}



getch();


return 0;
}

Upvotes: 1

Views: 19537

Answers (3)

user6740040
user6740040

Reputation: 11

you must use same array name i.e in[] instead of c[] and also remove ** before every variable.

Upvotes: 1

Josh Matthews
Josh Matthews

Reputation: 13036

You're seeing this because you're using c, which is an integer, as an array/pointer. The indirection error occurs because you're incorrectly dereferencing something that is not a pointer.

Upvotes: 4

Murali VP
Murali VP

Reputation: 6427

makes sense, variable c is not an array but an int, but there are c[8], c[6], etc.

Upvotes: 4

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