CODEWITHSUNDEEP
objective-ciosnsdecimalnumber
Karl
Karl

Reputation: 70

NSDecimalNumber: summing two NaNs results in overflow?

For some odd reason, I receive an NSDecimalNumberOverflowException from the following:

NSDecimalNumber *a = [NSDecimalNumber notANumber];
NSDecimalNumber *b = [NSDecimalNumber notANumber];
NSLog(@"%@",[a decimalNumberByAdding:b]);

This seems unexpected to me since the documentation for NSDecimalNumber's notANumber states that any arithmetic operation receiving a NaN as an argument returns a NaN...

I receive the same error for 1+NaN and NaN+1...thankfully 1+1 still gives 2.

Any ideas on what's going on?

Upvotes: 1

Views: 737

Answers (2)

user166390
user166390

Reputation:

Per posters request:

Could it be that it is creating a signaling NaN vs. a quiet NaN? These concepts exist in IEEE-754, not sure about NSDecimalNumber. What happens if you do [x decimalNumberByAdding: x] where x is the NSDecimalNumber created byte 1.0/0?

Upvotes: 1

NSResponder
NSResponder

Reputation: 16861

Why do you want to try to perform arithmetic on a NaN value? NaN is an error value.

Upvotes: 1

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