CODEWITHSUNDEEP
pythonselenium
ametefe
ametefe

Reputation: 113

Is there a way for a program to keep running when it hits an error in Selenium Python

I'm using Selenium to extract data from a website. The HTML is usually the same for all the shows but for certain shows it's different. Most should have 27 elements but some have lower amounts so it spits out an error

So, I'm asking if there is a way to break out of the section of the code before the error stops the program?

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time

Anime = input("Enter Anime:")
driver = webdriver.Chrome(executable_path=r"C:\Users\amete\Documents\chromedriver.exe")

driver.get("https://myanimelist.net/search/all?q=one%20piece&cat=all")
print(driver.title)

search = driver.find_element_by_xpath('//input[@name="q"]')
wait = WebDriverWait(driver, 20)
wait.until(EC.element_to_be_clickable((By.XPATH, '//input[@name="q"]')))
# Clears the field
search.send_keys(Keys.CONTROL, 'a')
search.send_keys(Keys.DELETE)

# The field is now cleared and the program can type whatever it wants
search.send_keys(Anime)
search.send_keys(Keys.RETURN)

#Accept the cookies
accept = driver.find_element_by_xpath('//*[@id="qc-cmp2-ui"]/div[2]/div/button[3]').click()

#  Added this wait
wait.until(EC.element_to_be_clickable((By.XPATH, '//h2[@id="anime"]//ancestor::div[@class="content-left"]//article[1]/div[contains(@class, "list")][1]/div[contains(@class, "information")]/a[1]')))
link = driver.find_element_by_xpath('//h2[@id="anime"]//ancestor::div[@class="content-left"]//article[1]/div[contains(@class, "list")][1]/div[contains(@class, "information")]/a[1]').click()

#Extracting information

#English Title + Jap Title + Display Score
English_Title = driver.find_element_by_xpath('//*[@id="contentWrapper"]/div[1]').text
#Jap_Title = driver.find_element_by_xpath('//*[@id="contentWrapper"]/div[1]/div/div[1]/div/h1/strong').text
Score = driver.find_element_by_xpath('//*[@id="content"]/table/tbody/tr/td[2]/div[1]/table/tbody/tr[1]/td/div[1]/div[1]/div[1]/div[1]/div[1]/div').text
Episodes = driver.find_element_by_xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[10]').text
print ("The English title :"+English_Title)
#print ("The Japanese title:"+Jap_Title)
print ("The Score of the Anime is:"+str(Score))
print (Episodes)

for i in range (7,28):
    Info = driver.find_element_by_xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div['+str(i)+']').text
    print (Info)

This is my code The website I'm using is MyAnimeList

Upvotes: 1

Views: 476

Answers (2)

Manusman
Manusman

Reputation: 57

This answers goes for any code in Python that causes an Exception. To catch an exception so that the program continues to run, use the try and except block. Within the try block put the code that may cause an exception. If an exception does trigger then the except block will run.

For example:

try:
    my_int = int(input("Enter a number: "))
except ValueError:
   print("Please enter a number not a text")

In the above example the user may enter an integer in to the command line and the code will run smoothly, but if a user instead enters a character or a string such as hello world the int() function will raise a ValueError which will be caught by the except block which will print an error message but won`t stop the program.

If multiple exceptions may occur you can use multiple except block to catch different kinds of exceptions. You can also use an empty except block that will catch any exception (though this is generally unadvisable).

If you want to learn more about try ecxpet blocks and exception handling in general in python see here.

Upvotes: 1

cruisepandey
cruisepandey

Reputation: 29362

Yes it is use try, except :

Let's say you think that the few line of code will have some issue (risky code), try to put that into try clause, like below :

try:
 for i in range (7,28):
    Info = driver.find_element_by_xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div['+str(i)+']').text
    print (Info)
except:
    pass

Even if it fails in a for loop, it will go to except that just says pass.

Upvotes: 1

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