CODEWITHSUNDEEP
pythonnumpymatrix
Ali Rojas
Ali Rojas

Reputation: 639

np.linalg.det() is the unique way to calc a matrix determinant?

If you just need to work with clasic 2D matrices, it's so fine to use numpay.mat because of their small and intuitive atributes:

import numpy as np

x = np.mat('1 2; 3 4')   # Matlab-like creating nomenclature.. cool!
y = np.mat('5 6; 7 8')

print(x.I)      # inverse matrix... cool!
print(x.T)      # transpose matrix... cool!
print(x*y)      # matrix multiplication... cool!
print(np.linalg.det(x))   # it's so tired to have to write all this to obtain the determinant!

Is there any fancy way to aboid writting "np.linalg.det(x)" to calc a determinant?

Upvotes: 1

Views: 173

Answers (1)

Mustafa Aydın
Mustafa Aydın

Reputation: 18306

You can assign a det variable for shortcut because functions are first-class objects:

>>> det = np.linalg.det
>>> det(x)
-2.0000000000000004

or perhaps better with from ... import ...:

>>> from numpy.linalg import det
>>> det(x)
-2.0000000000000004

Upvotes: 2

Related Questions