Reputation: 157
I'm having trouble coming up with a query to get the number of customers who purchased on multiple dates.
We're given a table of product purchases. Each row in the table represents an individual user product purchase.if the customer purchased two things on the same day that does not count as an upsell as they were purchased within a similar timeframe.
'transactions' table:
column | type |
---|---|
id | integer |
user_id | integer |
created_at | datetime |
product_id | integer |
quantity | integer |
I tried in this way
select count(*)
from
( select user_id
, count(date)
from
( SELECT user_id
, DATE(created_at) AS date
FROM transactions
GROUP BY 1,2
) S
group
by 1
having count(date)>1
) A
Upvotes: 0
Views: 12898
Reputation: 4491
Count the distinct dates per user, first, then count from table when the count is > 1.
See below:
WITH T as (select user_id,
count(distinct DATE(created_at)) as count
from transactions
GROUP BY user_id)
select count(*) from T where count > 1
Upvotes: 0
Reputation: 522741
I think you want:
SELECT COUNT(*)
FROM
(
SELECT user_id
FROM transactions
GROUP BY user_id
HAVING COUNT(DISTINCT DATE(created_at)) > 1
) t;
The subquery finds all users having transacted on more than one date, the outer query finds the count of such users.
Upvotes: 4