CODEWITHSUNDEEP
regex
nama asliku
nama asliku

Reputation: 107

regex if (text contain this text) match this

I have these two sentence

TAGGING ODP:-7.160792, 113.496069

TAGGING pel:-7.160792, 113.496069

I want to match -7.160792 part only if the full sentence contain "odp" in it.

I tried the following (?(?=odp)-\d+.\d+) but it doesn't work, i don't know why.

Any help is appreciated.

Upvotes: 2

Views: 78

Answers (4)

The fourth bird
The fourth bird

Reputation: 163372

The pattern (?(?=odp)\-\d+\.\d+) is using a conditional (? stating in the if clause:

If what is directly to the right from the current position is odp, then match -\d+.\d+

That can not match.

What you also could do is match odp followed by any char other than a digit using \D* and capture the digit part in a group.

\bodp\b\D*(-\d+\.\d+)\b

The pattern matches:

  • \bodp\b match odp between word boundaries to prevent a partial match
  • \D* Optionally match any char other than a digit
  • (-\d+\.\d+) Capture - and 1+ digits with a decimal part in group 1
  • \b A word boundary

Regex demo

Upvotes: 1

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 79115

You can use the regex, (?i)(?<=odp:)[^,]*.

Explanation:

  • (?i): Case-insenstitive flag
  • (?<=odp:): Positive lookbehind for odp:
  • [^,]*: Anything but ,

👉 If you want the match to be restricted to numbers only, you can use the regex, (?i)(?<=odp:)(?:-\d+.\d+)

Explanation:

  • (?i): Case-insenstitive flag
  • (?<=odp:): Positive lookbehind for odp:
  • (?:: Start non capturing group
    • -: Literal, -
    • \d+: 1+ digit(s)
    • .\d+: . followed by 1+ digit(s)
  • ): End non capturing group

👉 If the sign can be either + or -, you can use the regex, (?i)(?<=odp:)(?:[+-]\d+.\d+)

Upvotes: 1

Ryszard Czech
Ryszard Czech

Reputation: 18621

(?(?=odp)-\d+\.\d+) won't work because (?=odp) is a positive lookahead that imposes a constraint on the pattern on the right, -\d+\.\d+. Namely, it requires odp string to occur exactly at the same location where - and a number are expected.

Use

(?<=ODP:)-\d+\.\d+
ODP:(-\d+\.\d+)

If lookbehinds are supported, the first variant is more viable. Otherwise, another option with capturing groups is good to use.

And if odp can appear anywhere, even after the number:

(?i)^(?=.*odp).*(-\d+\.\d+)

This will capture the value into a group.

EXPLANATION

--------------------------------------------------------------------------------
  (?i)                     set flags for this block (case-
                           insensitive) (with ^ and $ matching
                           normally) (with . not matching \n)
                           (matching whitespace and # normally)
--------------------------------------------------------------------------------
  ^                        the beginning of the string
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    .*                       any character except \n (0 or more times
                             (matching the most amount possible))
--------------------------------------------------------------------------------
    odp                      'odp'
--------------------------------------------------------------------------------
  )                        end of look-ahead
--------------------------------------------------------------------------------
  .*                       any character except \n (0 or more times
                           (matching the most amount possible))
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    -                        '-'
--------------------------------------------------------------------------------
    \d+                      digits (0-9) (1 or more times (matching
                             the most amount possible))
--------------------------------------------------------------------------------
    \.                       '.'
--------------------------------------------------------------------------------
    \d+                      digits (0-9) (1 or more times (matching
                             the most amount possible))
--------------------------------------------------------------------------------
  )                        end of \1

Upvotes: 1

Gowthaman Ravindran
Gowthaman Ravindran

Reputation: 65

(?<=ODP:)(-\d+.\d+)

You can try using the negative look behind. This should solve for the code you ve provided.

Upvotes: 0

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