Reputation: 403
I have an array like:
[0,0,1,1,0,0,2,2,2,0...]
I have to pass for each element a letter in this form:
[A, B, C1, C2, D, E, F1, F2, F3, G...]
When the value is zero, or undefined or null need a new letter, otherwise need a new one again but as times as the same number stays there. There are two of 1 then I need C1, C2, later is there three of 2 so I need F three times.
Can you give me some hints to solve this issue?
Upvotes: 1
Views: 108
Reputation: 386550
You could take a closure over letter and count and return eiter the same letter as before with count or just the letter.
const
values = [0, 0, 1, 1, 2, 2, 3, 3, 3, 0],
result = values.map(((letter, count) => (v, i, { [i - 1]: prev }) => {
if (v) {
if (prev && v !== prev) {
++letter;
count = 1;
}
return letter.toString(36).toUpperCase() + count++;
}
if (count !== 1) ++letter;
count = 1;
return (letter++).toString(36).toUpperCase();
})(10, 1));
console.log(...result);
Upvotes: 2