Reputation: 6705
Is there any good reason why:
std::string input;
std::getline(std::cin, input);
the getline call won't wait for user input? Is the state of cin messed up somehow?
Upvotes: 8
Views: 5244
Reputation: 11
This code does not work:
#include <iostream>
#include <string>
int main()
{
int nr;
std::cout << "Number: ";
std::cin >> nr;
std::string input;
std::cout << "Write something: ";
getline(std::cin, input);
std::cout << "You input is: " << input << std::endl;
return 0;
}
This does work:
#include <iostream>
#include <string>
int main()
{
int nr;
std::cout << "Number: ";
std::cin >> nr;
std::string x;
std::getline(std::cin,x);
std::string input;
std::cout << "Write something: ";
getline(std::cin, input);
std::cout << "You input is: " << input << std::endl;
return 0;
}
Upvotes: 1
Reputation: 1
this occurred cause before std::getline(std::cin, input); there's newline char (/n). The getline reads until it encounters /n. Therefore it will read an empty string and return null without waiting for the users input.
To counter this we use an dummy getline, or cin.ignore(1, /n);
Upvotes: 0
Reputation: 39
I have tested the following code and it worked ok.
#include <iostream>
using namespace std;
int main()
{
string input;
getline(cin, input);
cout << "You input is: " << input << endl;
return 0;
}
I guess in your program that you might already have something in you input buffer.
Upvotes: 1
Reputation: 22114
Most likely you are trying to read a string after reading some other data, say an int
.
consider the input:
11
is a prime
if you use the following code:
std::cin>>number;
std::getline(std::cin,input)
the getline
will only read the newline after 11 and hence you will get the impression that it's not waiting for user input.
The way to resolve this is to use a dummy getline
to consume the new line after the number.
Upvotes: 7