CODEWITHSUNDEEP
python
M7kra
M7kra

Reputation: 31

Possible bug with os.path.join()

I'm having an incomprehensible error in my code. os.path.join will work with all paths I try, except those started with t after 'RC4'. Here is an example:

>>> os.path.join('RC4\static\posts', '0.png')
'RC4\\static\\posts\\0.png'
>>> os.path.join('RC4\templates\posts', '0.png')
'RC4\templates\\posts\\0.png'

If I split the first string, it works:

>>> os.path.join('RC4', 'templates\posts', '0.png')
'RC4\\templates\\posts\\0.png'

Upvotes: 0

Views: 919

Answers (3)

Stryder
Stryder

Reputation: 880

That is because '\t` is a special character representing a Tab (2 or 4 spaces). To avoid it being interpreted in that way, you can escape it using a backslash, like so

os.path.join('RC4\\templates\posts', '0.png')
>>> 'RC4\\templates\\posts\\0.png'

Although, according to xcodz-dot (comment), in a future version of python, you should escape the slash before posts as well, because an error will be raised otherwise, which also works in python 3.8.6:

os.path.join('RC4\\templates\\posts', '0.png')
>> 'RC4\\templates\\posts\\0.png'

Alternatively, you can place an 'r' in front of the string:

os.path.join(r'RC4\templates\posts', '0.png')
>> 'RC4\\templates\\posts\\0.png'

Upvotes: 1

Alexey S. Larionov
Alexey S. Larionov

Reputation: 7927

\t has a special meaning of TAB character (similarly to \n and other "escape" characters). That's why you're discouraged to manually use slashes in your path string.

You better use Path class with / operator

from pathlib import Path
posts_path = Path('RC4') / 'templates' / 'posts'
img_path = posts_path / '0.png'

Upvotes: 3

bereal
bereal

Reputation: 34282

\t is a tab char sequence. Use raw strings to avoid these issues:

os.path.join(r'RC4\templates\posts', '0.png')

Upvotes: 1

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