CODEWITHSUNDEEP
pythonpandasdataframeindexingcounting
PParker
PParker

Reputation: 1511

Simplest way to add repeating counter column to pandas dataframe

I have a datafame:

import pandas as pd

df = pd.DataFrame(
 {
 "key": ["K0", "K1", "K2", "K3", "K4", "K5", "K6", "K7", "K8", "K9",'K10', 'K11',],
 "team": ['a', 'd', 'w', 'a', 'c', 's', 'x', 'd', 'a', 'f', 'e', 'r'],
 }
)

df = 
    key team
0   K0  a
1   K1  d
2   K2  w
3   K3  a
4   K4  c
5   K5  s
6   K6  x
7   K7  d
8   K8  a
9   K9  f
10  K10 e
11  K11 r

What is the shortes / simples way to add a repeating counter column like this?:

    key team    counter
0    K0  a      0
1    K1  d      0
2    K2  w      0
3    K3  a      1
4    K4  c      1
5    K5  s      1
6    K6  x      2
7    K7  d      2
8    K8  a      2
9    K9  f      3
10   K10 e      3
11   K11 r      3

My feeling tells me, that there must be a one-line solution (maybe a bit longer). But all I can think of would be much longer and complex.

How would you approach this?

Upvotes: 0

Views: 190

Answers (1)

Anurag Dabas
Anurag Dabas

Reputation: 24322

try:

df['counter']=df.index//3

OR

If you have a custom index then you can use:

df['counter']=[x//3 for x in range(len(df))]

output of df:

    key     team    counter
0   K0      a       0
1   K1      d       0
2   K2      w       0
3   K3      a       1
4   K4      c       1
5   K5      s       1
6   K6      x       2
7   K7      d       2
8   K8      a       2
9   K9      f       3
10  K10     e       3
11  K11     r       3

Upvotes: 3

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