CODEWITHSUNDEEP
phpdatetimedatetime-format
Erics Nguyen
Erics Nguyen

Reputation: 380

PHP datetime create from format return wrong result

I need to check a string is match with some format, and i using DateTime::createFromFormat to enforce it. but it got some bugs.

example i have an date: 8/15/2020, i try to parse it to datetime object with format "d/m/Y", then i print it in to other format:

   DateTime::createFromFormat("d/m/Y", '8/15/2020')->format('d-m-Y')
   // result: 08-03-2021

that is wreig, because i read in php.net https://www.php.net/manual/en/datetime.createfromformat.php they said: d: day (1->30), m: month (1->12), Y: year (2020)

But i got an strange result? how it work? or it is the bug?

thank you for your answer.

Upvotes: 0

Views: 1243

Answers (3)

jspit
jspit

Reputation: 7683

I think the PHP manual is not correct.

The DateTime::getLastErrors() method generates a warning if the range for the day or month is exceeded. You can evaluate this. As an an example:

function DateTimeCreateFromStrictFormat($format, $input){
  $dt = DateTime::createFromFormat($format, $input);
  $errArr = DateTime::getLastErrors();
  return $errArr['warning_count']+$errArr['error_count'] ? false : $dt;
}
$dt = DateTimeCreateFromStrictFormat("d/m/Y", '8/15/2020');
var_dump($dt);  //bool(false)

$dt = DateTimeCreateFromStrictFormat("d/m/Y", '8/12/2020');
var_dump($dt);  //object(DateTime)#2 (3) { ["date"]=> string(26) "2020-12-08 10:34:34.000000" ..

Upvotes: 1

ADyson
ADyson

Reputation: 61784

i try to parse it to datetime object with format "d/m/Y"

... it's not clear why you tried it like that. 8/15/2020 is clearly m/d/Y. You need to parse it using the format it's actually written in.

You can output it again to d/m/Y afterwards - that is a separate operation.

DateTime::createFromFormat("m/d/Y", '8/15/2020')->format('d-m-Y')

Upvotes: 1

brice
brice

Reputation: 1881

Your format is day/month/year but there is no month 15 like the 8/15/2020 being given.

Did you mean 15/8/2020?

Upvotes: 1

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