CODEWITHSUNDEEP
regexsed
Dhanushka Ekanayake
Dhanushka Ekanayake

Reputation: 97

How to remove only the matching string part

I need to remove [PR:] from the [PR:Parker] which only print "ParkerS"

Note:[PR:xxxxxxx] "xxxxxxx" Part is changed time to time.

Upto now I have create a following sed command:

sed 's/[PR:]//g' | sed 's/[][]//g'

But it prints "arkerS" which missing the "P" in name too.

Upvotes: 1

Views: 242

Answers (2)

RavinderSingh13
RavinderSingh13

Reputation: 133458

1st solution: With awk, with your shown samples, please try following code once. Using gsub function to globally substituting starting [ followed by PR: and ] ending with NULL and printing rest of the values of line.

awk '{gsub(/^\[PR:|\]$/,"")} 1' Input_file

2nd solution: Using different field separator(s) in awk code to grab 2nd last value as per shown samples, try following.

awk -F':|\\]' '{print $(NF-1)}' Input_file

3rd solution: Using match function of awk try following. Matching regex /:[^]]*/ from 1st occurrence of : to before ] occurs and printing the matched part only as per requirement.

awk 'match($0,/:[^]]*/){print substr($0,RSTART+1,RLENGTH-1)}' Input_file

4th solution: Using bash capability of parameter expansion here. In case you have this value in a shell variable then this will be BEST solution to go for.

##If your shown sample is in a shell variable, use parameter expansion then.
var="[PR:Parker]"

##Create interim variable var1 to remove everything from starting till : here.
var1="${var##*:}"
echo "$var1"
Parker]

##Then on var1 remove ] and get needed value here.
echo "${var1%*]}"
Parker

5th solution: Using perl one liner try following, performing global substitution to remove starting [PR: and ending ] with null.

perl -pe 's/^\[PR:|\]$//g' Input_file

Upvotes: 3

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626747

You can use

sed 's/\[PR:\([^][]*\)]/\1/' <<< "[PR:Parker]"

Here, the \[PR:\([^][]*\)] matches [PR:, then any zero or more chars other than [ and ] are captured into Group 1 and a ] is matched, and the match is replaced with the Group 1 value (with \1 placeholder).

Or,

sed -E 's/\[PR:|]//g' <<< "[PR:Parker]"

See the online demo. Here, \[PR:|] matches either [PR: or ] and the s command removes them.

Upvotes: 2

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