Matlab is not running a .exe external program on Windows

Question

I'm trying to run .exe code inside Matlab terminal (R2018a) but I'm encountering some problems.

My .exe code runs normally on Windows cmd with the following generic command (an expected output file is created)

code.exe < input

In Matlab I tried 4 approaches:

system('code.exe < input');
dos('code.exe < input');
system('code.exe < input', '-echo');
system('set path=%path:C:\Program Files\MATLAB\R2018a\bin\win64;=% & code.exe < input');

They are returning the line below and no output file is created.

ans = -1.0737e+09

Adding the "&" character at the end of the line of attempt 1, as sugested by ref and many others, Matlab opens the Windows cmd in the correct folder but does not execute the .exe code properly (no processes are running in task manager), no output file is created, e.g.:

system('code.exe < input &');

I also tried the suggestion of this reference .exe run in matlab does not create two output files like it does when run in command prompt but I was not successful. This reference suggestion is also returning and no output file is created: "ans = -1.0737e+09"

Edit: According to this link, user Walter Roberson says "-1073741511 is hex C0000139 which appears to correspond to the Windows error code for "Entry point not found". That indicates that you either tried to execute something that was inherently not properly created (such as if you tried to directly execute the DLL that did not have a main program), or else that the program you executed tried to use a DLL that could not be found."

Any insights on how to resolve this? Thanks.

Answer 1

The answer from this link solved my problem.

Basically, You will have to create a batch file similar to the one below and change the Matlab path according to your version.

fid = fopen('myBatchFile.bat','w')
fprintf(fid,'%s\n','set path=%path:C:\Program Files\MATLAB\R2018a\bin\win64;=%');
fprintf(fid,'%s\n','code.exe < input')
fclose(fid)
system('myBatchFile.bat')