CODEWITHSUNDEEP
pythonpygamemenu
Ezabella Rose
Ezabella Rose

Reputation: 11

How to link between menu and main file in PyGame?

For example I have two files:

  1. main.py
  2. menu.py

main contains the game and menu contains a play button which to click to start the game.

I want to link between these two files for whenever I press play button the main starts to run without creating a new window.

I tried this:

main.py > running = False
          while running:
              (main.py works)

menu.py > from main import *
          if click:
              running = True

but it didn't worked for some reason..

Would you consider helping me out?

Upvotes: 0

Views: 1108

Answers (1)

furas
furas

Reputation: 142720

You should put code in functions so later you can run main.run(screen) to run game.

Minimal working example.

First it runs menu with red screen and when you click then it uses main.run(screen) to run main with green screen. When you click again then it uses return to go back to menu.

menu.py

import pygame
import main

def run(screen=None):
    print('[menu] run')

    if not screen:
        pygame.init()
        screen = pygame.display.set_mode((800,600))

    mainloop(screen)

def mainloop(screen):
    print('[menu] mainloop')

    running = True
    while running:

        print('running menu ...')

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                exit() # skip rest of code
            if event.type == pygame.MOUSEBUTTONDOWN:
                if event.button == 1:
                    main.run(screen)  # run game

        screen.fill((255,0,0))
        pygame.display.flip()


if __name__ == '__main__':
    run()

main.py

import pygame


def run(screen=None):
    print('[main] run')

    if not screen:
        pygame.init()
        screen = pygame.display.set_mode((800,600))

    mainloop(screen)

def mainloop(screen):
    print('[main] mainloop')

    running = True
    while running:

        print('running game ...')

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                exit() # skip rest of code
            if event.type == pygame.MOUSEBUTTONDOWN:
                if event.button == 1:
                    return  # go back to menu

        screen.fill((0,255,0))
        pygame.display.flip()

if __name__ == '__main__':
    run()

As you can see both code can be very similar. You could use the same code to create window with settings.py, results.py, etc. This way code can be simpler and later you can reuse some elements using classes.

To make it even more usefull you could dictionary config = {'screen': screen, ...} and send it to main.run(config), settings.run(config), results.run(config) and send it back with return config

Upvotes: 1

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