CODEWITHSUNDEEP
sql
Keydoo
Keydoo

Reputation: 57

SQL Excercise (movies with number of actors)

I am doing a SQL exercise with the task: Output all movies involving more than 9 actors. Specify the number of actors as well, sort by Number_Actors in ascending order, and then by movie title. Projection list: Film_Id, film title, Number_Actors. Unfortunately, I am stuck and don't know what I made wrong.

SELECT film_id, title, COUNT(film_id) AS number_actors 
FROM (
   SELECT film.title
   FROM film
   INNER JOIN film ON film_actor.film_id = film.film_id
   WHERE number_actors > 9
)
GROUP BY number_actors
ORDER BY number_actors, film

Table film with film_id as Primary Key

Table film_actor, which connects table film and actor

Table actor, with actor_id as Primary Key

Upvotes: 1

Views: 1944

Answers (2)

Carsten Massmann
Carsten Massmann

Reputation: 28196

It can be done even without a JOIN:

SELECT * FROM (
 SELECT film_id, title, 
       (SELECT COUNT(*) FROM film_actor Where film_id=f.film_id) number_actors 
 FROM film f ) f2
WHERE number_actors>9 ORDER BY number_actors

Upvotes: 0

forpas
forpas

Reputation: 164069

You can get the number of actors of each film by aggregation in the table film_actor.
If you also set the condition ...involving more than 9 actors in the HAVING clause then you get only the ids of the films that you want:

SELECT film_id, COUNT(*) Number_Actors
FROM film_actor
GROUP BY film_id
HAVING COUNT(*) > 9

You can join the table film to the above query:

SELECT f.film_id, f.title, t.Number_Actors
FROM film f
INNER JOIN (
    SELECT film_id, COUNT(*) Number_Actors
    FROM film_actor
    GROUP BY film_id
    HAVING COUNT(*) > 9
) t ON t.film_id = f.film_id
ORDER BY t.Number_Actors, f.title

Upvotes: 1

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