CODEWITHSUNDEEP
pythondictionaryinputformattingkey
user12916095
user12916095

Reputation:

How to get user to input phone number based on dictionary I created and get them to either enter key or value in format XXX-XXX-XXXX?

Okay, so first off, let me share my code and then I will ask my question. This is the code I have so far:

restaurant_dictionary = {2: ['a','A','b','B','c','C'],
                         3: ['d','D','e','E','f','F'],
                         4: ['g','G','h','H','i','I'],
                         5: ['j','J','k','K','l','L'],
                         6: ['m','M','n','N','o','O'],
                         7: ['p','P','q','Q','r','R','s','S'],
                         8: ['t','T','u','U','v','V'],
                         9: ['w','W','x','X','y','Y','z','Z']}

while key,value not in restaurant_dictionary:
    restaurant_number = raw_input("Please enter a phone number to translate:")

Now, my question is, I want a user to input a phone number in the format XXX-XXX-XXXX, and I want to first print, on the screen for the user to see, "Please enter a phone number to translate:". Then, I want to let them input 10 letters or digits for the phone number, based on the restaurant_dictionary I created above. I want to print the final phone number they input with dashes in between the first three and second three letters/digits and in between the second three and last four letters/digits.

Then, based on my restaurant dictionary above, it should be an easy matter of translating their input into only the digits that I use as keys for my values above. I started a while loop above, as you can see, because I figured that if they don't give valid input that corresponds to my dictionary, I should give them the opportunity to reenter the letter/digit.

Oh, and here is a sample of how the program should function when it is complete:

Enter a phone number to be translated:555-GET-FOOD↵

    555-438-3663↵

Enter a phone number to be translated:abc-flo-wers↵

    222-356-9377↵

Upvotes: 0

Views: 388

Answers (2)

martineau
martineau

Reputation: 123473

All you need is a reverse dictionary, which you could hardcode or create on-the-fly from a version the dictionary you have in your question with the uppercase letters removed (since there's no need to have both).

Here's a demo:

restaurant_dictionary = {2: ['a','b','c'],
                         3: ['d','e','f'],
                         4: ['g','h','i'],
                         5: ['j','k','l'],
                         6: ['m','n','o'],
                         7: ['p','q','r','s'],
                         8: ['t','u','v'],
                         9: ['w','x','y','z']}

# Construct a reverse mapping (i.e. letters to number)
letters = [letter for letters in restaurant_dictionary.values() for letter in letters]
rev_dict = {}
for letter in letters:
    for d, chars in restaurant_dictionary.items():
        if letter in chars:
            rev_dict[letter] = str(d)
            break

def convert(phone_num):
    return ''.join(rev_dict.get(char, char) for char in phone_num.lower())

#phone_num = list(input('Please enter your phone number: ')

for phone_num in ('555-GET-FOOD', 'abc-flo-wers', 'PYT-HON-TEST'):
    print(f'{phone_num} -> {convert(phone_num)}')

Output:

555-GET-FOOD -> 555-438-3663
abc-flo-wers -> 222-356-9377
PYT-HON-TEST -> 798-466-8378

Upvotes: 1

Matiiss
Matiiss

Reputation: 6156

Does this solve the issue:

restaurant_dictionary = {('a', 'b', 'c'):      2,
                         ('d', 'e', 'f'):      3,
                         ('g', 'h', 'i'):      4,
                         ('j', 'k', 'l'):      5,
                         ('m', 'n', 'o'):      6,
                         ('p', 'q', 'r', 's'): 7,
                         ('t', 'u', 'v'):      8,
                         ('w', 'x', 'y', 'z'): 9}

phone_nr = list(input('Please enter Your phone number: ').lower().replace('-', ''))

temp_lst = list()
for char in phone_nr:
    if char.isdigit():
        temp_lst.append(char)
        continue
    for key, item in restaurant_dictionary.items():
        if char in key:
            temp_lst.append(str(item))
            break

phone_nr = ''.join(temp_lst)
print(f'{phone_nr[:3]}-{phone_nr[3:6]}-{phone_nr[6:11]}')

to mention, at least in this case there was no need to include both capital and lowercase letters in the dictionary since the user input can be lowered altogether and then You could eval the whole thing against lowercase letters. it saves some space and time

Upvotes: 1

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