CODEWITHSUNDEEP
elixir
VR_1
VR_1

Reputation: 153

Get a value from struct inside list

I have a list as follows which has

[
  %Photos{
    url: "http://localhost:4000/test/img",
    user: "localhost:4000/test/img/123"}]

How do I get the result as "localhost:4000/test/img/123" which is a string?

Can anyone help me with this?

Thanks in advance.

Upvotes: 0

Views: 917

Answers (2)

Adam Millerchip
Adam Millerchip

Reputation: 23101

Assuming your list was a single element list as you quoted, you could pattern match it directly with:

[%Photos{url: url}] = list

This will put the url into the url variable. Example:

iex(2)> list = [%Photos{url: "http://localhost:4000/test/img", user: "localhost:4000/test/img/123"}]
[...]
iex(3)> [%Photos{url: url}] = list
[
  %Photos{
    url: "http://localhost:4000/test/img",
    user: "localhost:4000/test/img/123"
  }
]
iex(4)> url
"http://localhost:4000/test/img"

Upvotes: 3

Aleksei Matiushkin
Aleksei Matiushkin

Reputation: 121000

If the struct is under your control, you might implement Access for it and use get_in/2

get_in(list, [Access.all(), :url]

Also, the comprehension and pattern matching work well.

for %Photos{url: url} <- list, do: url

The last, but not the least way would be Enum.map/2

list |> Enum.map(& &1.url)

All the above return all urls in the list. To get to the specific one, use Enum.at/3 and/or pattern matching.

Upvotes: 6

Related Questions