CODEWITHSUNDEEP
regexcron
John Mark
John Mark

Reputation: 119

Regex cron. Detect if below 5 minutes

I have this regex:

^\h*(?:(?:\*|[0-9]+)\/0*(?:[0-4]))(?:\s+\*){4}

And I have these strings of cron jobs:

2,5,8,27,30,36,12,15,18,21,24,39,42 * * * * /bin/echo 0
5,5,8,27,30,36,12,15,18,21,24,39,42 * * * * /bin/echo 0
200,5,8,27,30,36,12,15,18,21,24,39,42 * * * * /bin/echo 0
27,30,36,12,15,18,21,24,39,42 * * * * /bin/echo 0
*/16 * * * * /bin/echo 0
*/13 * * * * /bin/echo 0
*/4 * * * * /bin/echo 0
*/2 * * * * /bin/echo 0
*/3 * * * * /bin/echo 0
110,5,8,27,30,36,12,15,18,21,24,39,42 * * * * /bin/echo 0

The result of the regex above is:

*/4 * * * * /bin/echo 0
*/2 * * * * /bin/echo 0
*/3 * * * * /bin/echo 0

But it does not detect other cron jobs that run below 4 minutes like this:

2,5,8,27,30,36,12,15,18,21,24,39,42 * * * * /bin/echo 0

So that one runs every 2 minutes, 5 minutes, 27, etc.

I would like to detect all lines of cron jobs that run below 5 minutes.

You can see my regex example here: https://regex101.com/r/iJmdvl/1

Thanks in advance.

Upvotes: 0

Views: 531

Answers (1)

Nefariis
Nefariis

Reputation: 3549

Here give this a try -

^(\*?\/?[0-4])(?:\s|,)

Which can be tested here -

https://regex101.com/r/U1MzYt/1/

This will just match the first part of each line if it contains */ conditionally and if it's followed (or starts with) [0-4].

Upvotes: 1

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