CODEWITHSUNDEEP
unixshellexecute
ptamzz
ptamzz

Reputation: 9355

Help to run a .sh script

I've my .sh script as

#!/bin/bash

if [ -z "$1" ] || [ -z "$2" ]; then
    echo "Usage: sync.sh DIRECTORY_LOCATION"
    exit 1
fi

DIRECTORY_LOCATION=$1

DEV_INSTANCE_IP=<some ip>

# Update data
scp -pR ${DEV_INSTANCE_IP}:${DIRECTORY_LOCATION}/* ${DIRECTORY_LOCATION}/

How do I run this script??

I tried sh sync.sh <path to directory> but it echos the line Usage: sync.sh DIRECTORY_LOCATION. Does that mean it's being run??

Upvotes: 0

Views: 214

Answers (3)

Dilettant
Dilettant

Reputation: 3335

Ahem, the script requires a second (bogus = never used) argument in the condition || [ -z "$2" ] if you delete that part, it should work as the authors meant it to be used, whatever this may be ;-) At least it should work the way you called it, namely sh sync.sh <path to directory>. And no, if you only provided this one argument in your version, it preinted the usage and exited undone. You can also just provide a second argument (as long as you do not mix-up with the two, i.e. providing the directory as the second arg would not help ...

Upvotes: 1

Fredrik Pihl
Fredrik Pihl

Reputation: 45634

yes it's running, -z flag means

-z STRING      True if string is empty.

If either first argument or second is empty --> exit.

one way of getting more information is to change the shebang to #!/bin/bash -x this will tell bash to print every line that is executed including the value of the parameters.

Upvotes: 1

user535883
user535883

Reputation:

The $1 in this script means it's expecting another entry for the DIRECTORY_LOCATION. So, you would need:

bash sync.sh directoryname

Also, instead of using sh scriptname.sh, it's better to do "chmod +x scriptname.sh".

Hope this helps!

Upvotes: 1

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