Reputation: 61
i was wondering if there is as faster way to check if given data is a vector or a matrix with zero rows or not, rather than,
if (is.vector(x)){
print('vector')
} else if {nrow(x) == 0){
print('0 rows')
} else {
print('matrix').
}
I am only interested in finding matrices fast.
Thanks a lot.
Upvotes: 0
Views: 178
Reputation: 18420
One method would be to use dim
:
!is.null(dim(x)) && all(dim(x)>0)
If x
is a vector, dim(x)
is NULL
.
I am not sure if this is faster than your own method and also not sure if this is a computation-intensive task at all.
Upvotes: 1