CODEWITHSUNDEEP
xmlxpath
billybobjo2
billybobjo2

Reputation: 1

XPath XML search root node for match, ignoring children

<?xml version="1.0" encoding="UTF-8"?>
<CATALOG YEAR="1988">
  <CD>
    <TITLE>Empire Burlesque</TITLE>
    <ARTIST>Bob Dylan</ARTIST>
    <COUNTRY>USA</COUNTRY>
    <COMPANY>Columbia</COMPANY>
    <PRICE>10.90</PRICE>
    <YEAR>1985</YEAR>
  </CD>
  <VINYL>
    <TITLE>Seventh Son of a Seventh Son</TITLE>
    <ARTIST>Iron Maiden</ARTIST>
    <COUNTRY>UK</COUNTRY>
    <COMPANY>EMI</COMPANY>
    <PRICE>10.20</PRICE>
    <YEAR>1988</YEAR>
  </VINYL>
</CATALOG>

In the above xml file, I want to check that the year of the Catalog is 1987, 1988, or 1989. However, when I use my search below

//CATALOG[matches(@YEAR, "198[789]")]

I get a match on both the Catalog year and the year of Seventh Son of a Seventh Son. How can I search only the root node? I tried searching with "self" or "." with no success. Thanks

Upvotes: 0

Views: 205

Answers (1)

zx485
zx485

Reputation: 29022

Your expression is a correct XPath-2.0 expression. So a valid XSLT-2.0 stylesheet could look like this:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="//CATALOG[matches(@YEAR, '198[789]')]">
    <xsl:copy-of select="." />
  </xsl:template>

</xsl:stylesheet>

This stylesheet matches and copies all root elements (probably one) with the given condition. Your expression is correct.

And if this doesn't work as desired, just use

/CATALOG[matches(@YEAR, '198[789]')]

This will (for sure) select the root element with the given properties.

Upvotes: 1

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