Reputation: 458
I'd like to make a Search<T>
extension method for IQueryable, but getting a LINQ expression runtime error, which cannot be translated.
public static IQueryable<T> Search<T>(this IQueryable<T> source, Func<T, string> expression, string search)
{
if (source == null)
throw new ArgumentNullException(nameof(source));
if (string.IsNullOrWhiteSpace(search))
return source;
return source.Where(x => EF.Functions.Like(expression(x), $"%{search}%"));
}
Usage:
dbContext.People.Search(x => x.Name, "Joe").ToList();
I guess the wrong line is the expression(x)
, but what is the correct way?
Upvotes: 0
Views: 1211
Reputation: 458
It is a tested and working solution.
public static IQueryable<T> Search<T>(this IQueryable<T> source, Expression<Func<T, string>> expression, string search)
{
if (source == null)
throw new ArgumentNullException(nameof(source));
if (string.IsNullOrWhiteSpace(search))
return source;
var property = typeof(T).GetProperty(((MemberExpression)expression.Body).Member.Name);
var parameter = Expression.Parameter(typeof(T));
var functions = Expression.Property(null, typeof(EF).GetProperty(nameof(EF.Functions)));
var like = typeof(DbFunctionsExtensions).GetMethod(nameof(DbFunctionsExtensions.Like),
new[] { functions.Type, typeof(string), typeof(string) });
Expression expressionProperty = Expression.Property(parameter, property.Name);
var body = Expression.Call(null, like, functions, expressionProperty, Expression.Constant($"%{search}%"));
return source.Where(Expression.Lambda<Func<T, bool>>(body, parameter));
}
Upvotes: 0
Reputation: 292
It doesn't use the Like function, but works fine as an extension.
var result = dbContex.Currencies.Search(x=>x.Symbol, "EUR").ToList();
public static IQueryable<T> Search<T>(this IQueryable<T> source, Expression<Func<T,string>> expression, string search)
{
if (source == null)
throw new ArgumentNullException(nameof(source));
if (string.IsNullOrWhiteSpace(search))
return source;
var method = typeof(string).GetMethod("Contains", new[] { typeof(string) });
var value = Expression.Constant(search, typeof(string));
var exp1 = Expression.Call(expression.Body, method, value);
var ex2 = Expression.Lambda<Func<T, bool>>(exp1, expression.Parameters[0]);
return source.Where(ex2);
}
Upvotes: 1