CODEWITHSUNDEEP
c++
inarticulatus
inarticulatus

Reputation: 175

"Call of overloaded function is ambiguous" even with different argument order

I have a function fun() I wish to overload in the same scope. As per the rules of overloading, different order of arguments should allow for the overloading of the function as mentioned here.

The Code:

#include "iostream"
using namespace std;
void fun(int i, float j)
{
        cout << "int,float";
}

void fun(float i, int j)
{
        cout << "float,int";
}

int main()
{
        fun(20,20);
}

Error:

error: call of overloaded ‘fun(int, int)’ is ambiguous
   15 |         fun(20,20);

Question:

Had there been only one function with argument fun(int, float), that would have been called as the best match, so why does it throw error in this case.

Upvotes: 1

Views: 2623

Answers (2)

Deyuan
Deyuan

Reputation: 56

The reason why you are facing this error is due to the data type of the arguments you have provided In this case

fun(20,20);

which are both int, int.

A correct function call in this scenario would be,

fun(20,20.0);

or

fun(20.0,20);

(edit) as mentioned by Ivan Vnucec it would be better to explicitly call the function with arguments that are float instead of double so call it in this way:

fun(20,20.0f);

or

fun(20.0f,20);

Upvotes: 2

MiniMik
MiniMik

Reputation: 268

You give two integers, so the compiler have to convert one into a float, but which function shall be taken?

int main()
{
  fun(20.0,20);
  fun( 20, 20.0);
}

these calls makes the compiler happy, since you tell which function shall be taken.

Upvotes: 2

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