Reputation: 5557
I’ve defined the following query which fetches me all items with an id
which is in a given list of ids
, and a status of either active
or retracted
.
const query = {
$and : [
{
$or: [
{
status: ‘active’,
},
{
status: ‘retracted’,
},
],
},
{
id: { $in: ids },
},
],
};
Each of these items has a parent_id
field, which can either be null
if the item does not have a parent, or can be the id of the parent.
I want my query to fetch all items with the ids
I supply, as well as their parent items, if such a parent exists.
For example, if I supply the following IDs
[1,2,3]
and item 2 has a parent with id 5, while item 1 and 3 have parent_id set to null
, I want my query to return the following items:
[1,2,3,5]
.
To achieve this I wrote the following query:
const collection = db.collection(‘myCollection’);
const data = await collection.aggregate([
{$match : query},
{
$lookup: {
from: ‘myCollection’,
let: { parentID: ‘$parent_id’},
pipeline: [
{
$match: {
$expr: {
$eq: [‘$id’, ‘$$parentID’],
},
},
},
as: ‘parent’,
},
},
]).sort(‘created_date’, ‘desc’).toArray();
return data;
However, this always returns null.
Sample Data:
[
{
id: 1,
parent_id: 3,
data: ‘bla bla’
},
{
id: 2,
parent_id: null,
data: ‘bla bla bla’
},
{
id: 3,
parent_id: null,
data: ‘bla’
}
]
Input: [1]
Output:
[
{
id: 1,
parent_id: 3,
data: ‘bla bla’
},
{
id: 3,
parent_id: null,
data: ‘bla’
}
]
Upvotes: 1
Views: 73
Reputation: 3920
You can try this. The input array is [2,3]
where 2 has parent id=1 and that is not in the input array. But the output array has the entry.
Working Playground
db.collection.aggregate([
{
$match: {
_id: {
$in: [
2,
3
]
}
}
},
{
$lookup: {
from: "collection",
localField: "p",
foreignField: "_id",
as: "parent"
}
},
{
$project: {
_id: 0,
id: {
$concatArrays: [
[
"$_id"
],
"$parent._id"
]
}
}
},
{
$unwind: "$id"
},
{
$sort: {
id: 1
}
}
])
Upvotes: 1
Reputation: 49975
The approach with $lookup
being run upon same collection should work however it gives you a nested array so you need few additional stages to flatten such array and get all elements as on result set:
db.collection.aggregate([
{
$match: { id: { $in: [1] } }
},
{
$lookup: {
from: "collection",
localField: "parent_id",
foreignField: "id",
as: "parent"
}
},
{
$project: {
all: {
$concatArrays: [
"$parent",
[ "$$ROOT" ]
]
}
}
},
{
$project: {
"all.parent": 0
}
},
{
$unwind: "$all"
},
{
$replaceRoot: {
newRoot: "$all"
}
}
])
Upvotes: 1
Reputation: 730
Your aggregation was malformed and lack some "]" for example closing the pipeline fied.
If you fix that the query works fine for me. Example
Upvotes: 1