CODEWITHSUNDEEP
javascriptarrays
William
William

Reputation: 39

Only Returns One Object In Array

if (lastUserMessage === '/love') {
    const love = [];
    newlove = prompt("What do you love?", "Thing you love.");
    love.push(newlove);
    localStorage.setItem('love', JSON.stringify(love));
    botMessage = 'Awesome.';
}

if (lastUserMessage === 'What do I. love?') {
    var love2 =   JSON.parse(localStorage.getItem("love"));
    botMessage = love2;
}

Its suppose to store more than 1 object in the array, but I only get 1 value back.

Upvotes: 0

Views: 476

Answers (1)

David
David

Reputation: 219047

Currently you always initialize your value to an empty array:

const love = [];

But it sounds like you expect it to retain the previously stored values in local storage. To do that, just initialize it to those values:

const love = JSON.parse(localStorage.getItem('love'));

As an extra step you might also do a null check on the stored array, just in case this is the first time the code was run and nothing is stored yet. Untested, but I suspect something like this may work:

const love = JSON.parse(localStorage.getItem('love') || '[]');

The idea being that getItem will return null if the item doesn't exist, so in that case you'd pass '[]' to JSON.parse and start with an empty array.

Upvotes: 1

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